In a neon discharge tube $2.9 \times 10^{18} \mathrm{Ne}^+$ ions move to the right each second while $1.2 \times 10^{18}$ electrons move to the left per second. Electron charge is $1.6 \times 10^{-19} \mathrm{C}$ . The current in the discharge tube
Text Solution
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$Charge on ions = 2.9 \times 10^{18} \times 1.6 \times 10^{-19} C$
$Charge on electrons = 1.2 \times 10^{18} \times 1.6 \times 10^{-19} \mathrm{C}$
$Total charge = 4.1 \times 1.6 \times 10^{-1} C$
$= 6.56 \times 10^{-1} C = 0.66 C$
$\text{Current} = \frac{\text{Charge}}{\text{Time}} = \frac{0.66 (C)}{1 (s)} = 0.66 \text{ A}$
The direction of current in a circuit is, by convention, taken along the direction in which positive charges flow. Hence the current in the discharge tube flows towards right.
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